As shown in the figure,a series circuit conne | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The total resistance of the circuit is $R_{total} = R_1 + R_2 = 44 \,\Omega + 36 \,\Omega = 80 \,\Omega$.The total reactance of the circuit is $X_

Vedclass · Accepted Answer

$144$

Vedclass · Answer

(C) The total resistance of the circuit is $R_{total} = R_1 + R_2 = 44 \,\Omega + 36 \,\Omega = 80 \,\Omega$.The total reactance of the circuit is $X_{total} = X_L - X_C = 90 \,\Omega - 30 \,\Omega = 60 \,\Omega$.The impedance of the circuit is $Z = \sqrt{R_{total}^2 + X_{total}^2} = \sqrt{80^2 + 60^2} = \sqrt{6400 + 3600} = \sqrt{10000} = 100 \,\Omega$.The $RMS$ current in the circuit is $I_{rms} = \frac{V_{rms}}{Z} = \frac{200 \,V}{100 \,\Omega} = 2 \,A$.The power dissipated in the coil is given by $P_{coil} = I_{rms}^2 	imes R_2$.Substituting the values,$P_{coil} = (2 \,A)^2 	imes 36 \,\Omega = 4 	imes 36 = 144 \,W$.

Similar Questions

In the given series $LCR$ circuit,if the value of $R$ is changed,then:

In an $LCR$ circuit,the capacitance is changed from $C$ to $4C$. For the same resonant frequency,the inductance should be changed from $L$ to:

Which one of the following curves represents the variation of impedance $(Z)$ with frequency $(f)$ in a series $LCR$ circuit?

$A$ circuit has three elements: a resistance of $11 \Omega$,a coil of inductive reactance $120 \Omega$,and a capacitive reactance of $120 \Omega$ in series,connected to an $A.C.$ source of $110 \, V, 60 \, Hz$. Which of the three elements has the minimum potential difference?

Consider the $L-C-R$ circuit given below. The circuit is driven by a $50 \,Hz, AC$ source with peak voltage $220 \,V$. If $R=400 \,\Omega, C=200 \,\mu F$ and $L=6 \,H$,the maximum current in the circuit is closest to ............ $A$.

Vedclass Test Series

Exam Paper Generator

Online Exam Module